Optimal. Leaf size=145 \[ \frac{4 a b \left (2 a^2+3 b^2\right ) \sin (c+d x)}{3 d}+\frac{a^2 \left (3 a^2+22 b^2\right ) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} x \left (24 a^2 b^2+3 a^4+8 b^4\right )+\frac{5 a^3 b \sin (c+d x) \cos ^2(c+d x)}{6 d}+\frac{a^2 \sin (c+d x) \cos ^3(c+d x) (a+b \sec (c+d x))^2}{4 d} \]
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Rubi [A] time = 0.312865, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {3841, 4074, 4047, 2637, 4045, 8} \[ \frac{4 a b \left (2 a^2+3 b^2\right ) \sin (c+d x)}{3 d}+\frac{a^2 \left (3 a^2+22 b^2\right ) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} x \left (24 a^2 b^2+3 a^4+8 b^4\right )+\frac{5 a^3 b \sin (c+d x) \cos ^2(c+d x)}{6 d}+\frac{a^2 \sin (c+d x) \cos ^3(c+d x) (a+b \sec (c+d x))^2}{4 d} \]
Antiderivative was successfully verified.
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Rule 3841
Rule 4074
Rule 4047
Rule 2637
Rule 4045
Rule 8
Rubi steps
\begin{align*} \int \cos ^4(c+d x) (a+b \sec (c+d x))^4 \, dx &=\frac{a^2 \cos ^3(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{4 d}+\frac{1}{4} \int \cos ^3(c+d x) (a+b \sec (c+d x)) \left (10 a^2 b+3 a \left (a^2+4 b^2\right ) \sec (c+d x)+b \left (a^2+4 b^2\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{5 a^3 b \cos ^2(c+d x) \sin (c+d x)}{6 d}+\frac{a^2 \cos ^3(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{4 d}-\frac{1}{12} \int \cos ^2(c+d x) \left (-3 a^2 \left (3 a^2+22 b^2\right )-16 a b \left (2 a^2+3 b^2\right ) \sec (c+d x)-3 b^2 \left (a^2+4 b^2\right ) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{5 a^3 b \cos ^2(c+d x) \sin (c+d x)}{6 d}+\frac{a^2 \cos ^3(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{4 d}-\frac{1}{12} \int \cos ^2(c+d x) \left (-3 a^2 \left (3 a^2+22 b^2\right )-3 b^2 \left (a^2+4 b^2\right ) \sec ^2(c+d x)\right ) \, dx+\frac{1}{3} \left (4 a b \left (2 a^2+3 b^2\right )\right ) \int \cos (c+d x) \, dx\\ &=\frac{4 a b \left (2 a^2+3 b^2\right ) \sin (c+d x)}{3 d}+\frac{a^2 \left (3 a^2+22 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{5 a^3 b \cos ^2(c+d x) \sin (c+d x)}{6 d}+\frac{a^2 \cos ^3(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{4 d}-\frac{1}{8} \left (-3 a^4-24 a^2 b^2-8 b^4\right ) \int 1 \, dx\\ &=\frac{1}{8} \left (3 a^4+24 a^2 b^2+8 b^4\right ) x+\frac{4 a b \left (2 a^2+3 b^2\right ) \sin (c+d x)}{3 d}+\frac{a^2 \left (3 a^2+22 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{5 a^3 b \cos ^2(c+d x) \sin (c+d x)}{6 d}+\frac{a^2 \cos ^3(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{4 d}\\ \end{align*}
Mathematica [A] time = 0.22748, size = 104, normalized size = 0.72 \[ \frac{12 \left (24 a^2 b^2+3 a^4+8 b^4\right ) (c+d x)+24 a^2 \left (a^2+6 b^2\right ) \sin (2 (c+d x))+96 a b \left (3 a^2+4 b^2\right ) \sin (c+d x)+32 a^3 b \sin (3 (c+d x))+3 a^4 \sin (4 (c+d x))}{96 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.063, size = 116, normalized size = 0.8 \begin{align*}{\frac{1}{d} \left ({a}^{4} \left ({\frac{\sin \left ( dx+c \right ) }{4} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) +{\frac{4\,{a}^{3}b \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{2}+2 \right ) \sin \left ( dx+c \right ) }{3}}+6\,{a}^{2}{b}^{2} \left ( 1/2\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) +1/2\,dx+c/2 \right ) +4\,a{b}^{3}\sin \left ( dx+c \right ) +{b}^{4} \left ( dx+c \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.19136, size = 147, normalized size = 1.01 \begin{align*} \frac{3 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{4} - 128 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} a^{3} b + 144 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} a^{2} b^{2} + 96 \,{\left (d x + c\right )} b^{4} + 384 \, a b^{3} \sin \left (d x + c\right )}{96 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.66033, size = 224, normalized size = 1.54 \begin{align*} \frac{3 \,{\left (3 \, a^{4} + 24 \, a^{2} b^{2} + 8 \, b^{4}\right )} d x +{\left (6 \, a^{4} \cos \left (d x + c\right )^{3} + 32 \, a^{3} b \cos \left (d x + c\right )^{2} + 64 \, a^{3} b + 96 \, a b^{3} + 9 \,{\left (a^{4} + 8 \, a^{2} b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.31884, size = 429, normalized size = 2.96 \begin{align*} \frac{3 \,{\left (3 \, a^{4} + 24 \, a^{2} b^{2} + 8 \, b^{4}\right )}{\left (d x + c\right )} - \frac{2 \,{\left (15 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 96 \, a^{3} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 72 \, a^{2} b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 96 \, a b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 9 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 160 \, a^{3} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 72 \, a^{2} b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 288 \, a b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 9 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 160 \, a^{3} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 72 \, a^{2} b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 288 \, a b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 15 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 96 \, a^{3} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 72 \, a^{2} b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 96 \, a b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{4}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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